2nd
Part
Plotting the data
series on a daily basis
From the data series there are prominent spikes, when seen, coming in about once a day.
Above on the 5th time
column is a typical spike
The 5 or 6 points connected by a thin
line
Plotting the difference in minutes from the preceding
day on the Y axis and the day on the X axis I got the following
chart.
The
spike came in about 50 minutes earlier each day and was not prominent enough to
be measured on some days. It was seen in the first part but not seen in the
second part of this chart.(14th to 23rd
bars)
From previous work by CM Edwards it was determined the
Velador is tracking the Sun.
http://www.sas.org/tcs/weeklyIssues_2007/2007-07-06/project1/index.html
http://hearth2.50megs.com/index.html
Using the universal gravitational formula
one
finds the Sun’s gravitational effect on the earth is abut 180 times larger than
the Moon’s. The Sun and Moon
comprise the bulk of gravitational effect on the earth but not all. The other
planets (especially Jupiter) and the stars have effects.
From my previous conceptions, the lecture presented to
SAS several years ago and information on my web sites, I have found that the
Velador is measuring the absolute motion of the Earth. The motion is primarily
produced by gravitational forces. In the working world these forces are
considered to be acceleration forces when change of motion is found. Everything
is changing its motion and this is caused by a force which is an accelerating
force. The prominent spike is caused by the Velador measuring the Sun’s force on
the Earth and the CCD through a change in motion
that the gravity produced. In this Velador setup (Stationary horizontal)
http://www.lanceosadchey.com/6a.htm
only the
change in motion is measured –the acceleration
effect—not the velocity.
Now
I must digress a bit and discuss the data in more detail. The data consists of 3 columns-(1)
time-(2) X pixel value-(3) Y pixel value. I made printed copies of the daily graphs
and stared at them for about two weeks. There were (time /X) graphs and (time/
Y) graphs and (XY) graphs however after a while I just used the XY graphs and if
studying an interesting series of points I referred back to the point on an (X
or Y) time graph to get the time it happened in. The XY graphs reflected the
actual movement of the spot of light from the laser on the CCD. This setup uses
just one CCD which gives a 2 dimensional view. If there were another axis then a
3D view could be obtained.
As
it turned out were 3 patterns of points. One I called a cluster. The points were
clustered in a close group. Then there was the spike. This showed a sudden thin
spike in the pattern of the points. And then there was the arc. Which was a
series of points thicker that the spike and moving in an arc shape. These were the only patterns I found in
the data.
Below there are 2 XY charts
Above shows several clusters, and an arc and a spike.
Above are a cluster
and a spike.
From previous studies it was determined that when the
CCD was directly facing the rising or setting sun a cluster was produced. When
the sun moved up or down from the set or rise position and the CCD was initially
pointing to the set or rise, then an arc was formed. When the sun got close to
the edge of the CCD i.e. the plane of the CCD was on edge to the sun, a spike
occurred as the sun passed the CCD plane.
I surmise
the following:: If the plane of the sun CCD
is not edge on there would be a smaller spike produced, that is harder to
visualize and I suppose if the CCD passed by the sun facing the sun either
forward or backwards no spike happened only a cluster..
All
these groups of points represent the accelerating motion of the CCD. However
this spike, when it could be seen, occurred generally earlier each day. It
disappeared about ˝ the time.
From this aspect of the analysis we are seeing a spike
which occurs earlier each day and disappears part of the
time.
What natural phenomenon occurs earlier each day? The
rising of the stars does. Stars
rise earlier by about 4 minutes each day.
http://www.uni.edu/morgans/astro/course/Notes/section1/new2.html
That is a clue. The stars do not follow the neat 24 hour
time of the sun. This process we are figuring out does not follow sun time. What
process could cause this and explain the disappearance of the signal at
times?
The
placement of the spot of light on the CCD depends on
the sun’s (and everything else producing a
gravitational effect on the Earth) position in relation to the orientation of
the CCD.
Consider the Earth Moon system. The Moon revolves around the Earth about every 27 1/3 days.
And
the Earth goes around the Moon in that same period. The Earth Moon barycenter is
the common point of rotation. This point is about 1000 miles down inside the
Earth.
This point is constantly changing position inside the
Earth from the Earths rotational effects and varying position of the Moon.
However the Earth does make a small orbit around this point. The Earth is also
traveling around the sun. Many think the shape of this path is like a
cycloid.
However if you viewed the system from a far distance as
both sun and moon travel around the sun, since the velocity of the system around
the sun is so much greater than the velocity of the earth around the barycenter,
it would be difficult to see the slight weaving pattern of the Earths path. Like
the red path in the middle illustration only stretched out even more, not the
path in the bottom illustration.
Now lets look at what position the small flat rectangular CCD would be in due to this small barycenter revolution.
At
times once every 27 1/3 days the CCD would face
the sun then move to an edge on position then facing away from the sun then at
another edge on view. The CCD is in motion from this effect constantly but lets
think of it as jumping to a new position say every day and staying there until
the next jump.
Also the CCD is in
(Latitude 43.70N longitude 72.28W)
AND
the earth is moving around the sun in its orbit which we shall ignore here for
now.
So
lets imagine we are looking at the CCD as it moves on the Earth moving about 30
degrees in its orbit far from us as it goes around the Sun. And it –the CCD –is
moving with the earth in a small barycenter circle. Of course this circle is
spread out due to the orbit around the sun. but its still a small spiral-like
circle. This motion takes 27 1/3 days to complete and in effect moves the CCD a
bit closer to the point it picks up the sun by 24 hours / 27 1/3 days. This is
about 52 minutes and about the time the spike comes in earlier on the data. And
at times the CCD is oriented not in a position to detect the sun but more or
less facing the sun and not able to “see” the spike. Obviously the distance and
velocity of the moon as affected on the earth by gravity would affect the data.
I looked up 3 different ephemeredes and it seems they all disagreed as to where
the moon was and what it was doing for motion. Lunar ranging was not cooperative
with me for data. I think the epmeredes are computer generated and not
consistent. I am sure that correct
values would be consistent with the data. A computer model should demonstrate
this relationship of the position of the CCD and the various motions of the
earth produced by the acceleration of gravity.
The
spike pick up represents the suns position from the rotation of the earth on its
axis. The earlier time of pick up comes from the Earth’s barycenter
rotation.
Its somewhat mind-boggling to consider that you could be standing next to this Velador and see the sun visually appear in the South at noon each day (very close to noon using the equation of time) and yet the Velador shows the spike of the sun about 52 minutes earlier each day.
This Web Page Created with PageBreeze Free HTML Editor